Média = ( 4.P1 + 4.P2 + 4.P3 + 3.T ) / 15
T representa a média aritmética dos 3
trabalhos
t1 - implementação de máquina
de estados
t2 - sincronização de relógios
t3 - controlador de sistema contínuo
P1 P2 P3 t1 t2 t3
T
media exame final
Cindy
D
3.0 9.0 9.0
10+10+10=30 10.0 7.6 -- 7.5
Daniel K
A
8.4 9.5 9.5
10+10+ 0=20 6.7 8.6 --
8.5
Denis R S
J
5.0 5.0 1.5 xx+xx+xx=
7.8 4.6 3.9 4.5
Eduardo R
M 8.8 10.0
8.5
10+10+10=30 10.0 9.3 -- 9.5
Francisco A
B
6.0 9.0 7.5
10+10+ 9=29 9.7 7.9 --
8.0
Gelson O
P
8.5 10.0 10.0
10+10+ 9=29 9.7
9.5 -- 9.5
Ivando G L
J
8.5 5.5 7.5
10+10+ 9=29 9.7
7.7 -- 7.5
Lucas S
J
5.6 9.0 8.5
10+10+ 0=20 6.7
7.5 -- 7.5
Marcelo L
E
8.9 5.0 7.5
10+10+10=30 10.0 7.7
-- 7.5
Marco A
P
8.0 7.5 8.5
10+10+10=30 10.0 8.4 -- 8.5
Marlon R
G
9.0 8.5 5.5
10+10+ 9=29 9.7
8.1 -- 8.0
Rafael O
B
8.5 6.0 8.0
9+ 0+ 0=9 3.0 6.6
-- 6.5
Rodrigo M
M
9.2 9.3 7.5
10+10+10=30 10.0 8.9 -- 9.0
Rogerio L A
B
7.5 3.5 7.5 xx+xx+xx=
9.8 6.9 -- 7.0
Tales
R
9.0 8.0 8.0
10+10+10=30 10.0 8.7 -- 8.5
Victor B
R
7.8 8.5 9.5
10+10+10=30 10.0 8.9 -- 9.0
Vinicius
S 9.3 9.5 9.5
10+10+10=30 10.0 9.5 -- 9.5
Vitor Hugo M
L
9.3 10.0 9.5
10+10+10=30 10.0 9.7 -- 9.5
Vitor Jose C
B
6.3 5.0 6.3
10+10+ 0=20 6.7
6.0 -- 6.0
Adan C
A
0+ 0+ 0=0 0.0
0.0 -- 0.0
Juliano
T
7.9 7.0 8.0
10+10+ 5=25 8.3
7.8 -- 8.0
Leonardo C
S
3.5 6.0 8.0
10+10+10=30 10.0 6.7 -- 6.5
Marcelo H S
S
8.3 9.5 8.5
10+10+ 0=20 6.7 8.4 -- 8.5
Marcos T
P
4.8 8.0 6.5 xx+xx+xx=
7.8 6.7 -- 6.5
Paulo E F
C
6.0 6.0 8.3 0+ 0+ 0=0 0.0
5.4 9.0 7.0
Thiago A
S
7.5 8.0 8.3 xx+xx+xx= 10.0
8.3 -- 8.5
Wesckley H X
S
6.3 1.0 0.0 0+10+ 0=10
3.3 2.6 -- 2.5
Yuri
V
8.3 9.0 8.8
10+10+ 5=25 8.3 8.6 --
8.5